Y=x2-62x+952

Solution for Y=x2-62x+952 equation:

=Y2-62Y+952

We move all terms to the left:

-(Y2-62Y+952)=0

We add all the numbers together, and all the variables

-(+Y^2-62Y+952)=0

We get rid of parentheses

-Y^2+62Y-952=0

We add all the numbers together, and all the variables

-1Y^2+62Y-952=0

a = -1; b = 62; c = -952;
Δ = b2-4ac
Δ = 622-4·(-1)·(-952)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-6}{2*-1}=\frac{-68}{-2}
=+34
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+6}{2*-1}=\frac{-56}{-2}
=+28
$