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=Y2-6Y-40
We move all terms to the left:
-(Y2-6Y-40)=0
We add all the numbers together, and all the variables
-(+Y^2-6Y-40)=0
We get rid of parentheses
-Y^2+6Y+40=0
We add all the numbers together, and all the variables
-1Y^2+6Y+40=0
a = -1; b = 6; c = +40;
Δ = b2-4ac
Δ = 62-4·(-1)·40
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-14}{2*-1}=\frac{-20}{-2} =+10 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+14}{2*-1}=\frac{8}{-2} =-4 $
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