Z(4x+2)=5(x+3)+4

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Solution for Z(4x+2)=5(x+3)+4 equation: 



(4Z+2)=5(Z+3)+4

We move all terms to the left:

(4Z+2)-(5(Z+3)+4)=0

We get rid of parentheses

4Z-(5(Z+3)+4)+2=0



We calculate terms in parentheses: -(5(Z+3)+4), so:

5(Z+3)+4

We multiply parentheses

5Z+15+4

We add all the numbers together, and all the variables

5Z+19

Back to the equation:

-(5Z+19)



We get rid of parentheses

4Z-5Z-19+2=0

We add all the numbers together, and all the variables

-1Z-17=0

We move all terms containing Z to the left, all other terms to the right

-Z=17

Z=17/-1

Z=-17

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