Z+(-3+2i)=z(5-4i)

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Solution for Z+(-3+2i)=z(5-4i) equation:


Simplifying
Z + (-3 + 2i) = z(5 + -4i)

Remove parenthesis around (-3 + 2i)
Z + -3 + 2i = z(5 + -4i)

Reorder the terms:
-3 + Z + 2i = z(5 + -4i)
-3 + Z + 2i = (5 * z + -4i * z)

Reorder the terms:
-3 + Z + 2i = (-4iz + 5z)
-3 + Z + 2i = (-4iz + 5z)

Solving
-3 + Z + 2i = -4iz + 5z

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + Z + 3 + 2i = -4iz + 3 + 5z

Reorder the terms:
-3 + 3 + Z + 2i = -4iz + 3 + 5z

Combine like terms: -3 + 3 = 0
0 + Z + 2i = -4iz + 3 + 5z
Z + 2i = -4iz + 3 + 5z

Reorder the terms:
Z + 2i = 3 + -4iz + 5z

Add '-2i' to each side of the equation.
Z + 2i + -2i = 3 + -4iz + -2i + 5z

Combine like terms: 2i + -2i = 0
Z + 0 = 3 + -4iz + -2i + 5z
Z = 3 + -4iz + -2i + 5z

Reorder the terms:
Z = 3 + -2i + -4iz + 5z

Simplifying
Z = 3 + -2i + -4iz + 5z

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