Z+(1+3i)=2-5i

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Solution for Z+(1+3i)=2-5i equation:


Simplifying
Z + (1 + 3i) = 2 + -5i

Remove parenthesis around (1 + 3i)
Z + 1 + 3i = 2 + -5i

Reorder the terms:
1 + Z + 3i = 2 + -5i

Solving
1 + Z + 3i = 2 + -5i

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + Z + -1 + 3i = 2 + -1 + -5i

Reorder the terms:
1 + -1 + Z + 3i = 2 + -1 + -5i

Combine like terms: 1 + -1 = 0
0 + Z + 3i = 2 + -1 + -5i
Z + 3i = 2 + -1 + -5i

Combine like terms: 2 + -1 = 1
Z + 3i = 1 + -5i

Add '-3i' to each side of the equation.
Z + 3i + -3i = 1 + -5i + -3i

Combine like terms: 3i + -3i = 0
Z + 0 = 1 + -5i + -3i
Z = 1 + -5i + -3i

Combine like terms: -5i + -3i = -8i
Z = 1 + -8i

Simplifying
Z = 1 + -8i

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