Z+(4/z+1)=3

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Solution for Z+(4/z+1)=3 equation: 



+(4/Z+1)=3

We move all terms to the left:

+(4/Z+1)-(3)=0



Domain of the equation: Z+1)!=0

Z∈R



We get rid of parentheses

4/Z+1-3=0

We multiply all the terms by the denominator


1*Z-3*Z+4=0

We add all the numbers together, and all the variables

-2Z+4=0

We move all terms containing Z to the left, all other terms to the right

-2Z=-4

Z=-4/-2

Z=+2

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