Z+3(2z+5)=29

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Solution for Z+3(2z+5)=29 equation:


Simplifying
Z + 3(2z + 5) = 29

Reorder the terms:
Z + 3(5 + 2z) = 29
Z + (5 * 3 + 2z * 3) = 29
Z + (15 + 6z) = 29

Reorder the terms:
15 + Z + 6z = 29

Solving
15 + Z + 6z = 29

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + Z + -15 + 6z = 29 + -15

Reorder the terms:
15 + -15 + Z + 6z = 29 + -15

Combine like terms: 15 + -15 = 0
0 + Z + 6z = 29 + -15
Z + 6z = 29 + -15

Combine like terms: 29 + -15 = 14
Z + 6z = 14

Add '-6z' to each side of the equation.
Z + 6z + -6z = 14 + -6z

Combine like terms: 6z + -6z = 0
Z + 0 = 14 + -6z
Z = 14 + -6z

Simplifying
Z = 14 + -6z

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