Z-2=5/(1-z)

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Solution for Z-2=5/(1-z) equation: 



-2=5/(1-Z)

We move all terms to the left:

-2-(5/(1-Z))=0



Domain of the equation: (1-Z))!=0

We move all terms containing Z to the left, all other terms to the right

-Z)!=-1

Z!=-1/1

Z!=-1

Z∈R



We add all the numbers together, and all the variables

-(5/(-1Z+1))-2=0

We multiply all the terms by the denominator


-(5-2*(-1Z+1))=0



We calculate terms in parentheses: -(5-2*(-1Z+1)), so:

5-2*(-1Z+1)

determiningTheFunctionDomain
-2*(-1Z+1)+5

We multiply parentheses

2Z-2+5

We add all the numbers together, and all the variables

2Z+3

Back to the equation:

-(2Z+3)



We get rid of parentheses

-2Z-3=0

We move all terms containing Z to the left, all other terms to the right

-2Z=3

Z=3/-2

Z=-1+1/2

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