Z/(3+z)=3

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Solution for Z/(3+z)=3 equation:



/(3+Z)=3
We move all terms to the left:
/(3+Z)-(3)=0
Domain of the equation: (3+Z)!=0
We move all terms containing Z to the left, all other terms to the right
Z!=-3
Z∈R
We add all the numbers together, and all the variables
/(Z+3)-3=0
We multiply all the terms by the denominator
-3*(Z+3)+=0
We add all the numbers together, and all the variables
-3*(Z+3)=0
We multiply parentheses
-3Z-9=0
We move all terms containing Z to the left, all other terms to the right
-3Z=9
Z=9/-3
Z=-3

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