Z/(3+z)=3

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Solution for Z/(3+z)=3 equation: 



/(3+Z)=3

We move all terms to the left:

/(3+Z)-(3)=0



Domain of the equation: (3+Z)!=0

We move all terms containing Z to the left, all other terms to the right

Z!=-3

Z∈R



We add all the numbers together, and all the variables

/(Z+3)-3=0

We multiply all the terms by the denominator


-3*(Z+3)+=0

We add all the numbers together, and all the variables

-3*(Z+3)=0

We multiply parentheses

-3Z-9=0

We move all terms containing Z to the left, all other terms to the right

-3Z=9

Z=9/-3

Z=-3

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