Z/2(z+4)=3z-6

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Solution for Z/2(z+4)=3z-6 equation:



/2(Z+4)=3Z-6
We move all terms to the left:
/2(Z+4)-(3Z-6)=0
Domain of the equation: 2(Z+4)!=0
Z∈R
We get rid of parentheses
/2(Z+4)-3Z+6=0
We multiply all the terms by the denominator
-3Z*2(Z+4)+6*2(Z+4)+=0
We add all the numbers together, and all the variables
-3Z*2(Z+4)+6*2(Z+4)=0
Wy multiply elements
-6Z^2(Z+12Z(Z=0

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