Z/2+1=6-z2

Solution for Z/2+1=6-z2 equation:

/2+1=6-Z2

We move all terms to the left:

/2+1-(6-Z2)=0

We add all the numbers together, and all the variables

-(-1Z^2+6)+1+/2=0

We get rid of parentheses

1Z^2-6+1+/2=0

We multiply all the terms by the denominator


1Z^2*2-6*2+1*2+=0

We add all the numbers together, and all the variables

1Z^2*2=0

Wy multiply elements

2Z^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Z=\frac{-b}{2a}=\frac{0}{4}=0$