Z/6+2+z-1/6-2=z/6-z

Solution for Z/6+2+z-1/6-2=z/6-z equation:

/6+2+Z-1/6-2=Z/6-Z

We move all terms to the left:

/6+2+Z-1/6-2-(Z/6-Z)=0


Domain of the equation: 6-Z)!=0

We move all terms containing Z to the left, all other terms to the right

-Z)!=-6

Z!=-6/1

Z!=-6

Z∈R


We add all the numbers together, and all the variables

Z-(-1Z+Z/6)+2-2+/6-1/6=0

We add all the numbers together, and all the variables

Z-(-1Z+Z/6)+/6-1/6=0

We get rid of parentheses

Z+1Z-Z/6+/6-1/6=0

We multiply all the terms by the denominator


Z*6+1Z*6-Z-1+=0

We add all the numbers together, and all the variables

-1Z+Z*6+1Z*6=0

Wy multiply elements

-1Z+6Z+6Z=0

We add all the numbers together, and all the variables

11Z=0

Z=0/11

Z=0