Z3+3z2+Z+3=0

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Solution for Z3+3z2+Z+3=0 equation: 



3+3Z^2++3=0

We add all the numbers together, and all the variables

3Z^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Z=\frac{-b}{2a}=\frac{0}{6}=0$

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