Z=(2+X)k

Solution for Z=(2+X)k equation:

=(2+Z)Z

We move all terms to the left:

-((2+Z)Z)=0

We add all the numbers together, and all the variables

-((Z+2)Z)=0


We calculate terms in parentheses: -((Z+2)Z), so:

(Z+2)Z

We multiply parentheses

Z^2+2Z

Back to the equation:

-(Z^2+2Z)


We get rid of parentheses

-Z^2-2Z=0

We add all the numbers together, and all the variables

-1Z^2-2Z=0

a = -1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-1}=\frac{0}{-2}
=0
$
$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-1}=\frac{4}{-2}
=-2
$