Z=2/5u+2;u

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Solution for Z=2/5u+2;u equation: 



=2/5Z+2Z

We move all terms to the left:

-(2/5Z+2Z)=0



Domain of the equation: 5Z+2Z)!=0

Z∈R



We add all the numbers together, and all the variables

-(+2Z+2/5Z)=0

We get rid of parentheses

-2Z-2/5Z=0

We multiply all the terms by the denominator


-2Z*5Z-2=0

Wy multiply elements

-10Z^2-2=0

a = -10; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-10)·(-2)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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