Z=2/5u+2;u

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Solution for Z=2/5u+2;u equation:



=2/5Z+2Z
We move all terms to the left:
-(2/5Z+2Z)=0
Domain of the equation: 5Z+2Z)!=0
Z∈R
We add all the numbers together, and all the variables
-(+2Z+2/5Z)=0
We get rid of parentheses
-2Z-2/5Z=0
We multiply all the terms by the denominator
-2Z*5Z-2=0
Wy multiply elements
-10Z^2-2=0
a = -10; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-10)·(-2)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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