Z=4/5u+7;u

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Solution for Z=4/5u+7;u equation:



=4/5Z+7Z
We move all terms to the left:
-(4/5Z+7Z)=0
Domain of the equation: 5Z+7Z)!=0
Z∈R
We add all the numbers together, and all the variables
-(+7Z+4/5Z)=0
We get rid of parentheses
-7Z-4/5Z=0
We multiply all the terms by the denominator
-7Z*5Z-4=0
Wy multiply elements
-35Z^2-4=0
a = -35; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-35)·(-4)
Δ = -560
Delta is less than zero, so there is no solution for the equation

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