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a(49-a)=180
We move all terms to the left:
a(49-a)-(180)=0
We add all the numbers together, and all the variables
a(-1a+49)-180=0
We multiply parentheses
-1a^2+49a-180=0
a = -1; b = 49; c = -180;
Δ = b2-4ac
Δ = 492-4·(-1)·(-180)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-41}{2*-1}=\frac{-90}{-2} =+45 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+41}{2*-1}=\frac{-8}{-2} =+4 $
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