a(b+c-d)=ab+ac-ad

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Solution for a(b+c-d)=ab+ac-ad equation: 


Simplifying
a(b + c + -1d) = ab + ac + -1ad
(b * a + c * a + -1d * a) = ab + ac + -1ad
(ab + ac + -1ad) = ab + ac + -1ad

Add '-1ab' to each side of the equation.
ab + ac + -1ab + -1ad = ab + ac + -1ab + -1ad

Reorder the terms:
ab + -1ab + ac + -1ad = ab + ac + -1ab + -1ad

Combine like terms: ab + -1ab = 0
0 + ac + -1ad = ab + ac + -1ab + -1ad
ac + -1ad = ab + ac + -1ab + -1ad

Reorder the terms:
ac + -1ad = ab + -1ab + ac + -1ad

Combine like terms: ab + -1ab = 0
ac + -1ad = 0 + ac + -1ad
ac + -1ad = ac + -1ad

Add '-1ac' to each side of the equation.
ac + -1ac + -1ad = ac + -1ac + -1ad

Combine like terms: ac + -1ac = 0
0 + -1ad = ac + -1ac + -1ad
-1ad = ac + -1ac + -1ad

Combine like terms: ac + -1ac = 0
-1ad = 0 + -1ad
-1ad = -1ad

Add 'ad' to each side of the equation.
-1ad + ad = -1ad + ad

Combine like terms: -1ad + ad = 0
0 = -1ad + ad

Combine like terms: -1ad + ad = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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