a*(a+1)*(a+2)*(a+3)=28

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Solution for a*(a+1)*(a+2)*(a+3)=28 equation: 



a*(a+1)*(a+2)*(a+3)=28

We move all terms to the left:

a*(a+1)*(a+2)*(a+3)-(28)=0

We move all terms containing a to the left, all other terms to the right

a*(a+1)*(a+2)*(a+3)=28

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