a+(a-2)=(a+5)(a+3)

Solution for a+(a-2)=(a+5)(a+3) equation:

a+(a-2)=(a+5)(a+3)

We move all terms to the left:

a+(a-2)-((a+5)(a+3))=0

We get rid of parentheses

a+a-((a+5)(a+3))-2=0

We multiply parentheses ..

-((+a^2+3a+5a+15))+a+a-2=0


We calculate terms in parentheses: -((+a^2+3a+5a+15)), so:

(+a^2+3a+5a+15)

We get rid of parentheses

a^2+3a+5a+15

We add all the numbers together, and all the variables

a^2+8a+15

Back to the equation:

-(a^2+8a+15)


We add all the numbers together, and all the variables

2a-(a^2+8a+15)-2=0

We get rid of parentheses

-a^2+2a-8a-15-2=0

We add all the numbers together, and all the variables

-1a^2-6a-17=0

a = -1; b = -6; c = -17;
Δ = b2-4ac
Δ = -62-4·(-1)·(-17)
Δ = -32
Delta is less than zero, so there is no solution for the equation