a+(a-3)=(9+2)-(a+1)

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Solution for a+(a-3)=(9+2)-(a+1) equation: 



a+(a-3)=(9+2)-(a+1)

We move all terms to the left:

a+(a-3)-((9+2)-(a+1))=0

We add all the numbers together, and all the variables

a+(a-3)-(11-(a+1))=0

We get rid of parentheses

a+a-(11-(a+1))-3=0



We calculate terms in parentheses: -(11-(a+1)), so:

11-(a+1)

determiningTheFunctionDomain
-(a+1)+11

We get rid of parentheses

-a-1+11

We add all the numbers together, and all the variables

-1a+10

Back to the equation:

-(-1a+10)



We add all the numbers together, and all the variables

2a-(-1a+10)-3=0

We get rid of parentheses

2a+1a-10-3=0

We add all the numbers together, and all the variables

3a-13=0

We move all terms containing a to the left, all other terms to the right

3a=13

a=13/3

a=4+1/3

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