a+(a-3)=(a+2)-(9+1)

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Solution for a+(a-3)=(a+2)-(9+1) equation: 



a+(a-3)=(a+2)-(9+1)

We move all terms to the left:

a+(a-3)-((a+2)-(9+1))=0

We add all the numbers together, and all the variables

a+(a-3)-((a+2)-10)=0

We get rid of parentheses

a+a-((a+2)-10)-3=0



We calculate terms in parentheses: -((a+2)-10), so:

(a+2)-10

We get rid of parentheses

a+2-10

We add all the numbers together, and all the variables

a-8

Back to the equation:

-(a-8)



We add all the numbers together, and all the variables

2a-(a-8)-3=0

We get rid of parentheses

2a-a+8-3=0

We add all the numbers together, and all the variables

a+5=0

We move all terms containing a to the left, all other terms to the right

a=-5

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