a+(b+c)=(b+c)+a

Solution for a+(b+c)=(b+c)+a equation:

Simplifying
a + (b + c) = (b + c) + a

Remove parenthesis around (b + c)
a + b + c = (b + c) + a

Remove parenthesis around (b + c)
a + b + c = b + c + a

Reorder the terms:
a + b + c = a + b + c

Add '-1a' to each side of the equation.
a + b + -1a + c = a + b + -1a + c

Reorder the terms:
a + -1a + b + c = a + b + -1a + c

Combine like terms: a + -1a = 0
0 + b + c = a + b + -1a + c
b + c = a + b + -1a + c

Reorder the terms:
b + c = a + -1a + b + c

Combine like terms: a + -1a = 0
b + c = 0 + b + c
b + c = b + c

Add '-1b' to each side of the equation.
b + -1b + c = b + -1b + c

Combine like terms: b + -1b = 0
0 + c = b + -1b + c
c = b + -1b + c

Combine like terms: b + -1b = 0
c = 0 + c
c = c

Add '-1c' to each side of the equation.
c + -1c = c + -1c

Combine like terms: c + -1c = 0
0 = c + -1c

Combine like terms: c + -1c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.