a+(n-4)d=1

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Solution for a+(n-4)d=1 equation:


Simplifying
a + (n + -4) * d = 1

Reorder the terms:
a + (-4 + n) * d = 1

Reorder the terms for easier multiplication:
a + d(-4 + n) = 1
a + (-4 * d + n * d) = 1
a + (-4d + dn) = 1

Solving
a + -4d + dn = 1

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '4d' to each side of the equation.
a + -4d + 4d + dn = 1 + 4d

Combine like terms: -4d + 4d = 0
a + 0 + dn = 1 + 4d
a + dn = 1 + 4d

Add '-1dn' to each side of the equation.
a + dn + -1dn = 1 + 4d + -1dn

Combine like terms: dn + -1dn = 0
a + 0 = 1 + 4d + -1dn
a = 1 + 4d + -1dn

Simplifying
a = 1 + 4d + -1dn

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