a+10(12-a)+18=(12-a)+10a

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Solution for a+10(12-a)+18=(12-a)+10a equation: 



a+10(12-a)+18=(12-a)+10a

We move all terms to the left:

a+10(12-a)+18-((12-a)+10a)=0

We add all the numbers together, and all the variables

a+10(-1a+12)-((-1a+12)+10a)+18=0

We multiply parentheses

a-10a-((-1a+12)+10a)+120+18=0



We calculate terms in parentheses: -((-1a+12)+10a), so:

(-1a+12)+10a

We add all the numbers together, and all the variables

10a+(-1a+12)

We get rid of parentheses

10a-1a+12

We add all the numbers together, and all the variables

9a+12

Back to the equation:

-(9a+12)



We add all the numbers together, and all the variables

-9a-(9a+12)+138=0

We get rid of parentheses

-9a-9a-12+138=0

We add all the numbers together, and all the variables

-18a+126=0

We move all terms containing a to the left, all other terms to the right

-18a=-126

a=-126/-18

a=+7

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