a+16+(3a-12)+(10a-20)=180

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Solution for a+16+(3a-12)+(10a-20)=180 equation: 



a+16+(3a-12)+(10a-20)=180

We move all terms to the left:

a+16+(3a-12)+(10a-20)-(180)=0

We add all the numbers together, and all the variables

a+(3a-12)+(10a-20)-164=0

We get rid of parentheses

a+3a+10a-12-20-164=0

We add all the numbers together, and all the variables

14a-196=0

We move all terms containing a to the left, all other terms to the right

14a=196

a=196/14

a=14

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