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a+16+(3a-12)+(10a-20)=180
We move all terms to the left:
a+16+(3a-12)+(10a-20)-(180)=0
We add all the numbers together, and all the variables
a+(3a-12)+(10a-20)-164=0
We get rid of parentheses
a+3a+10a-12-20-164=0
We add all the numbers together, and all the variables
14a-196=0
We move all terms containing a to the left, all other terms to the right
14a=196
a=196/14
a=14
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