a+3=4(5+a)

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Solution for a+3=4(5+a) equation: 



a+3=4(5+a)

We move all terms to the left:

a+3-(4(5+a))=0

We add all the numbers together, and all the variables

a-(4(a+5))+3=0



We calculate terms in parentheses: -(4(a+5)), so:

4(a+5)

We multiply parentheses

4a+20

Back to the equation:

-(4a+20)



We get rid of parentheses

a-4a-20+3=0

We add all the numbers together, and all the variables

-3a-17=0

We move all terms containing a to the left, all other terms to the right

-3a=17

a=17/-3

a=-5+2/3

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