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a+5a*2a=6
We move all terms to the left:
a+5a*2a-(6)=0
Wy multiply elements
10a^2+a-6=0
a = 10; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·10·(-6)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*10}=\frac{-1-\sqrt{241}}{20} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*10}=\frac{-1+\sqrt{241}}{20} $
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