a+b=4(7b-3a)/a

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Solution for a+b=4(7b-3a)/a equation:


x in (-oo:+oo)

a+b = (4*(7*b-(3*a)))/a // - (4*(7*b-(3*a)))/a

a-((4*(7*b-(3*a)))/a)+b = 0

a-4*a^-1*(7*b-3*a)+b = 0

a-4*a^-1*(7*b-3*a)+b = 0

a-28*a^-1*b+b+12 = 0

a-28*a^-1*b+b+12 = 0

x belongs to the empty set

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