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0-(4/(x^2))+1 = 0;x
x
A+B-3;C-2*B+5;3*A-(2*C)-2
A+B-3;C-2*B+5;3*A-(2*B)-2
(2*x^2-(7*x))*(4*x^2+9+12)*(x^2+1) = 0;x
x
1;1;1;3;1;0
| 6/10t=44 | | -34=8x-2 | | 10-(x-1)=10 | | 5k+7-5k-4= | | 2x-3+7+7=3x-10 | | -8t+14=-9t | | f(x)=l-3l+3 | | 5x-17-3x-5=90 | | y-x=-18 | | 4b=34 | | 5x-17=90 | | 5.95+24.95=50.00 | | 8-.5x=.25x-7 | | 0.09xX=76.49 | | 7x+5-x+2= | | 6(5m^2+12)= | | 3(x+4)=84 | | 28=r/2 | | N-1/3=7/9 | | -45=-9(2x-3) | | 8x-5(-4x+3)=13 | | 9a-3a+8= | | y=-2(-3)+2 | | 2x^2+4=y-15 | | 5z+3+2z+1= | | 6x^2+6-5x=0 | | 17u=9u+64 | | 9.2-1.7x=2.3x+1.2 | | (3x^2)+6x=45 | | -1/5b=-1/5 | | 2y+14=3y+2 | | 2+5=50 |