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a-(2a-5)/3=3+(a-4)
We move all terms to the left:
a-(2a-5)/3-(3+(a-4))=0
We multiply all the terms by the denominator
a*3-(2a-5)-((3+(a-4)))*3=0
Wy multiply elements
3a-(2a-5)-((3+(a-4)))*3=0
We get rid of parentheses
3a-2a-((3+(a-4)))*3+5=0
We add all the numbers together, and all the variables
a-((3+(a-4)))*3+5=0
We move all terms containing a to the left, all other terms to the right
a-((3+(a-4)))*3=-5
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