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a-(5a+1)=8-2(1a-3)
We move all terms to the left:
a-(5a+1)-(8-2(1a-3))=0
We add all the numbers together, and all the variables
a-(5a+1)-(8-2(a-3))=0
We get rid of parentheses
a-5a-(8-2(a-3))-1=0
We calculate terms in parentheses: -(8-2(a-3)), so:We add all the numbers together, and all the variables
8-2(a-3)
determiningTheFunctionDomain -2(a-3)+8
We multiply parentheses
-2a+6+8
We add all the numbers together, and all the variables
-2a+14
Back to the equation:
-(-2a+14)
-4a-(-2a+14)-1=0
We get rid of parentheses
-4a+2a-14-1=0
We add all the numbers together, and all the variables
-2a-15=0
We move all terms containing a to the left, all other terms to the right
-2a=15
a=15/-2
a=-7+1/2
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