a-1/4=8/a+3

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Solution for a-1/4=8/a+3 equation:


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

a-(1/4) = 8/a+3 // - 8/a+3

a-(8/a)-(1/4)-3 = 0

a-8*a^-1-1/4-3 = 0

1*a^1-8*a^-1-13/4*a^0 = 0

(1*a^2-13/4*a^1-8*a^0)/(a^1) = 0 // * a^2

a^1*(1*a^2-13/4*a^1-8*a^0) = 0

a^1

a^2+(-13/4)*a-8 = 0

a^2+(-13/4)*a-8 = 0

DELTA = (-13/4)^2-(-8*1*4)

DELTA = 681/16

DELTA > 0

a = ((681/16)^(1/2)-(-13/4))/(1*2) or a = (-(-13/4)-(681/16)^(1/2))/(1*2)

a = ((681/16)^(1/2)+13/4)/2 or a = (13/4-(681/16)^(1/2))/2

a in { (13/4-(681/16)^(1/2))/2, ((681/16)^(1/2)+13/4)/2}

a in { (13/4-(681/16)^(1/2))/2, ((681/16)^(1/2)+13/4)/2 }

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