a-4(2-3a)=-4+3(a+2)

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Solution for a-4(2-3a)=-4+3(a+2) equation:



a-4(2-3a)=-4+3(a+2)
We move all terms to the left:
a-4(2-3a)-(-4+3(a+2))=0
We add all the numbers together, and all the variables
a-4(-3a+2)-(-4+3(a+2))=0
We multiply parentheses
a+12a-(-4+3(a+2))-8=0
We calculate terms in parentheses: -(-4+3(a+2)), so:
-4+3(a+2)
determiningTheFunctionDomain 3(a+2)-4
We multiply parentheses
3a+6-4
We add all the numbers together, and all the variables
3a+2
Back to the equation:
-(3a+2)
We add all the numbers together, and all the variables
13a-(3a+2)-8=0
We get rid of parentheses
13a-3a-2-8=0
We add all the numbers together, and all the variables
10a-10=0
We move all terms containing a to the left, all other terms to the right
10a=10
a=10/10
a=1

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