a-4/4-5(a-3)/10=3a+12/5

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Solution for a-4/4-5(a-3)/10=3a+12/5 equation:


a in (-oo:+oo)

a-((5*(a-3))/10)-(4/4) = 3*a+12/5 // - 3*a+12/5

a-((5*(a-3))/10)-(3*a)-(4/4)-(12/5) = 0

(-1/2)*(a-3)+a-3*a-12/5-1 = 0

a-1/2*(a-3)-3*a-12/5-1 = 0

(-1/2*5*(a-3))/5+(5*a)/5+(-3*5*a)/5-12/5+(-1*5)/5 = 0

5*a-1/2*5*(a-3)-3*5*a-1*5-12 = 0

5/2*a-15*a-12-5+15/2 = 0

15/2-25/2*a-12-5 = 0

-25/2*a-5-9/2 = 0

-25/2*a-19/2 = 0

(-25/2*a-19/2)/5 = 0

(-25/2*a-19/2)/5 = 0 // * 5

-25/2*a-19/2 = 0

-25/2*a-19/2 = 0 // + 19/2

-25/2*a = 19/2 // : -25/2

a = 19/2/(-25/2)

a = -19/25

a = -19/25

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