a-5=(2a+4)/9

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Solution for a-5=(2a+4)/9 equation: 



a-5=(2a+4)/9

We move all terms to the left:

a-5-((2a+4)/9)=0

We multiply all the terms by the denominator


a*9)-((2a+4)-5*9)=0

We add all the numbers together, and all the variables

a*9)-((2a+4)=0

Wy multiply elements

9a^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{18}=0$

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