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x in (-oo:+oo)
a-(6*b) = (3/10)*(2*a-(9*b)) // - (3/10)*(2*a-(9*b))
a-((3/10)*(2*a-(9*b)))-(6*b) = 0
(-3/10)*(2*a-9*b)+a-6*b = 0
a-3/10*(2*a-9*b)-6*b = 0
a-3/10*(2*a-9*b)-6*b = 0
2/5*a+27/10*b-6*b = 0
2/5*a-33/10*b = 0
2/5*a-33/10*b = 0
x belongs to the empty set
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