a/3=(a+4)/5

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Solution for a/3=(a+4)/5 equation: 



a/3=(a+4)/5

We move all terms to the left:

a/3-((a+4)/5)=0

We calculate fractions


5a^2/()+(-((a+4)*3)/()=0



We calculate terms in parentheses: +(-((a+4)*3)/(), so:

-((a+4)*3)/(

We multiply all the terms by the denominator


-((a+4)*3)



We calculate terms in parentheses: -((a+4)*3), so:

(a+4)*3

We multiply parentheses

3a+12

Back to the equation:

-(3a+12)



We get rid of parentheses

-3a-12

Back to the equation:

+(-3a-12)



We get rid of parentheses

5a^2/()-3a-12=0

We multiply all the terms by the denominator


5a^2-3a*()-12*()=0

We add all the numbers together, and all the variables

5a^2-3a*()=0

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