a/4=5-(a-2)/5

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Solution for a/4=5-(a-2)/5 equation: 



a/4=5-(a-2)/5

We move all terms to the left:

a/4-(5-(a-2)/5)=0

We calculate fractions


5a^2/()+(-(5-(a-2)*4)/()=0



We calculate terms in parentheses: +(-(5-(a-2)*4)/(), so:

-(5-(a-2)*4)/(

We multiply all the terms by the denominator


-(5-(a-2)*4)



We calculate terms in parentheses: -(5-(a-2)*4), so:

5-(a-2)*4

determiningTheFunctionDomain
-(a-2)*4+5

We multiply parentheses

-4a+8+5

We add all the numbers together, and all the variables

-4a+13

Back to the equation:

-(-4a+13)



We get rid of parentheses

4a-13

Back to the equation:

+(4a-13)



We get rid of parentheses

5a^2/()+4a-13=0

We multiply all the terms by the denominator


5a^2+4a*()-13*()=0

We add all the numbers together, and all the variables

5a^2+4a*()=0

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