a/5=(a-3)/2

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Solution for a/5=(a-3)/2 equation: 



a/5=(a-3)/2

We move all terms to the left:

a/5-((a-3)/2)=0

We calculate fractions


2a^2/()+(-((a-3)*5)/()=0



We calculate terms in parentheses: +(-((a-3)*5)/(), so:

-((a-3)*5)/(

We multiply all the terms by the denominator


-((a-3)*5)



We calculate terms in parentheses: -((a-3)*5), so:

(a-3)*5

We multiply parentheses

5a-15

Back to the equation:

-(5a-15)



We get rid of parentheses

-5a+15

Back to the equation:

+(-5a+15)



We get rid of parentheses

2a^2/()-5a+15=0

We multiply all the terms by the denominator


2a^2-5a*()+15*()=0

We add all the numbers together, and all the variables

2a^2-5a*()=0

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