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a1=-10a^2=-5
We move all terms to the left:
a1-(-10a^2)=0
We add all the numbers together, and all the variables
-(-10a^2)+a=0
We get rid of parentheses
10a^2+a=0
a = 10; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·10·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*10}=\frac{-2}{20} =-1/10 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*10}=\frac{0}{20} =0 $
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