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a2+12a+11=a+
We move all terms to the left:
a2+12a+11-(a+)=0
We add all the numbers together, and all the variables
a2+12a-(+a)+11=0
We add all the numbers together, and all the variables
a^2+12a-(+a)+11=0
We get rid of parentheses
a^2+12a-a+11=0
We add all the numbers together, and all the variables
a^2+11a+11=0
a = 1; b = 11; c = +11;
Δ = b2-4ac
Δ = 112-4·1·11
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{77}}{2*1}=\frac{-11-\sqrt{77}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{77}}{2*1}=\frac{-11+\sqrt{77}}{2} $
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