a2+28a+27=0

Solution for a2+28a+27=0 equation:

a2+28a+27=0

We add all the numbers together, and all the variables

a^2+28a+27=0

a = 1; b = 28; c = +27;
Δ = b2-4ac
Δ = 282-4·1·27
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-26}{2*1}=\frac{-54}{2}
=-27
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+26}{2*1}=\frac{-2}{2}
=-1
$