a2+9=-6a

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Solution for a2+9=-6a equation: 



a2+9=-6a

We move all terms to the left:

a2+9-(-6a)=0

We add all the numbers together, and all the variables

a^2-(-6a)+9=0

We get rid of parentheses

a^2+6a+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-6}{2}=-3$

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