a2+b2=900

Solution for a2+b2=900 equation:

2+A2=900

We move all terms to the left:

2+A2-(900)=0

We add all the numbers together, and all the variables

A^2-898=0

a = 1; b = 0; c = -898;
Δ = b2-4ac
Δ = 02-4·1·(-898)
Δ = 3592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3592}=\sqrt{4*898}=\sqrt{4}*\sqrt{898}=2\sqrt{898}$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{898}}{2*1}=\frac{0-2\sqrt{898}}{2}
=-\frac{2\sqrt{898}}{2}
=-\sqrt{898}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{898}}{2*1}=\frac{0+2\sqrt{898}}{2}
=\frac{2\sqrt{898}}{2}
=\sqrt{898}
$