a2-16a+64=(9-8)(9-8)

Solution for a2-16a+64=(9-8)(9-8) equation:

a2-16a+64=(9-8)(9-8)

We move all terms to the left:

a2-16a+64-((9-8)(9-8))=0

We add all the numbers together, and all the variables

a2-16a+64-(11)=0

We add all the numbers together, and all the variables

a^2-16a+53=0

a = 1; b = -16; c = +53;
Δ = b2-4ac
Δ = -162-4·1·53
Δ = 44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{44}=\sqrt{4*11}=\sqrt{4}*\sqrt{11}=2\sqrt{11}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{11}}{2*1}=\frac{16-2\sqrt{11}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{11}}{2*1}=\frac{16+2\sqrt{11}}{2}
$