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a2-7a=a+20
We move all terms to the left:
a2-7a-(a+20)=0
We add all the numbers together, and all the variables
a^2-7a-(a+20)=0
We get rid of parentheses
a^2-7a-a-20=0
We add all the numbers together, and all the variables
a^2-8a-20=0
a = 1; b = -8; c = -20;
Δ = b2-4ac
Δ = -82-4·1·(-20)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*1}=\frac{-4}{2} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*1}=\frac{20}{2} =10 $
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