a2=150

Solution for a2=150 equation:

a2=150

We move all terms to the left:

a2-(150)=0

We add all the numbers together, and all the variables

a^2-150=0

a = 1; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·1·(-150)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*1}=\frac{0-10\sqrt{6}}{2}
=-\frac{10\sqrt{6}}{2}
=-5\sqrt{6}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*1}=\frac{0+10\sqrt{6}}{2}
=\frac{10\sqrt{6}}{2}
=5\sqrt{6}
$