a2=16+5(2-1)

Solution for a2=16+5(2-1) equation:

a2=16+5(2-1)

We move all terms to the left:

a2-(16+5(2-1))=0

We add all the numbers together, and all the variables

a2-(16+51)=0

We add all the numbers together, and all the variables

a^2-67=0

a = 1; b = 0; c = -67;
Δ = b2-4ac
Δ = 02-4·1·(-67)
Δ = 268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{268}=\sqrt{4*67}=\sqrt{4}*\sqrt{67}=2\sqrt{67}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{67}}{2*1}=\frac{0-2\sqrt{67}}{2}
=-\frac{2\sqrt{67}}{2}
=-\sqrt{67}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{67}}{2*1}=\frac{0+2\sqrt{67}}{2}
=\frac{2\sqrt{67}}{2}
=\sqrt{67}
$