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a2=836
We move all terms to the left:
a2-(836)=0
We add all the numbers together, and all the variables
a^2-836=0
a = 1; b = 0; c = -836;
Δ = b2-4ac
Δ = 02-4·1·(-836)
Δ = 3344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3344}=\sqrt{16*209}=\sqrt{16}*\sqrt{209}=4\sqrt{209}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{209}}{2*1}=\frac{0-4\sqrt{209}}{2} =-\frac{4\sqrt{209}}{2} =-2\sqrt{209} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{209}}{2*1}=\frac{0+4\sqrt{209}}{2} =\frac{4\sqrt{209}}{2} =2\sqrt{209} $
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